Two resistances 20,Omega and 50,Omega and a p | vedclass

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(A) In a $DC$ circuit,after a long time $(t 	o \infty)$,the inductor acts as a short circuit (a wire with zero resistance) because the current become

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(A) In a $DC$ circuit,after a long time $(t 	o \infty)$,the inductor acts as a short circuit (a wire with zero resistance) because the current becomes steady and the induced $EMF$ across the inductor becomes zero.Since the $50\,\Omega$ resistor is connected in parallel with the pure inductor,the entire current will flow through the path of least resistance,which is the inductor.Therefore,the potential difference across the $50\,\Omega$ resistor becomes zero.Consequently,the final current flowing through the $50\,\Omega$ resistor is $0\,A$.

Two resistances $20\,\Omega$ and $50\,\Omega$ and a pure inductance of $50\,H$ are connected to a $10\,V$ battery through a key as shown in the figure. The key is closed at $t = 0$. Find the final value of current in the $50\,\Omega$ resistor.

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